User talk:Who2010

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-- Wikimedia Commons Welcome (talk) 18:08, 22 February 2016 (UTC)[reply]

SVG (Scalable Vector Graphics)[edit]

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Please use SVG

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EugeneZelenko (talk) 14:48, 22 March 2016 (UTC)[reply]

File:Konvergenzschema für Reihen.pdf[edit]

File:Konvergenzschema für Reihen.pdf has been listed at Commons:Deletion requests so that the community can discuss whether it should be kept or not. We would appreciate it if you could go to voice your opinion about this at its entry.

If you created this file, please note that the fact that it has been proposed for deletion does not necessarily mean that we do not value your kind contribution. It simply means that one person believes that there is some specific problem with it, such as a copyright issue. Please see Commons:But it's my own work! for a guide on how to address these issues.

Please remember to respond to and – if appropriate – contradict the arguments supporting deletion. Arguments which focus on the nominator will not affect the result of the nomination. Thank you!

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EugeneZelenko (talk) 14:33, 30 October 2016 (UTC)[reply]

No problem, you may delete it. It was changed into a svg-image by Stephan Kulla Who2010 (talk) 15:31, 13 November 2016 (UTC)[reply]

https://de.wikipedia.org/wiki/Datei:Satz_von_Rolle2.svg[edit]

Hello Who2010!

I'd like to ask you what software you used for the curves, and if possible, would like to request another one.

With the function

f(x)={\begin{cases}\quad 2x-a&{\text{für }}x<a\\\quad a&{\text{für }}x=a\\-2x+a&{\text{für }}x>a\end{cases}}

the special case of a differentiated function that is not continuous is being emphasized. I'd like to add this case on the article of "Satz von Rolle" as it shows, that even if a differentiated function isn't continuous around 0, it still definitly has to have the value 0.

--Sanitiy (talk) 15:36, 7 November 2016 (UTC)[reply]

Hi Sanitiy!

Thanks for your feedback! I used inkscape 0.91 to make the picture. With this software you can easily modify the picture if you want.

Concerning your example: I am not sure if I understand you correct. But I don't think there is an differentiable function F with F'=f. Except for a=0, and in this case f is continuous in a. But maybe I am wrong, and you can give me such a function F. ;-)

My third counterexample

f:[0,1]\to \mathbb {R} ,\ f(x)={\begin{cases}x&x\leq {\tfrac {1}{2}}\\1-x&x>{\tfrac {1}{2}}\end{cases}}

shows, that the Rolle Theorem needn't work, if f isn't differentiable just in a single point. So I don't think there is an extension of the theorem for this case! But maybe I missunderstood your argumentation.

Greetings Who2010 (talk) 22:22, 7 November 2016 (UTC)[reply]

User talk:Who2010

SVG (Scalable Vector Graphics)[edit]

File:Konvergenzschema für Reihen.pdf[edit]

https://de.wikipedia.org/wiki/Datei:Satz_von_Rolle2.svg[edit]

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