<nowiki>John Russell, duque de Bedford; John Russell, 6th Duke of Bedford; John Russell of Bedford; Джон Рассел, 6-й герцог Бедфорда; John Russell, 6. Duke of Bedford; John Russell, 6ed Dug Bedford; John Russell of Bedford; 第六代貝德福德公爵約翰·羅素; John Russell of Bedford; John Russell; ジョン・ラッセル; جون راسل; John Russell of Bedford; John Russell of Bedford; John Russell of Bedford; John Russell; John Russell, VI duca di Bedford; John Russell; John Russell of Bedford; John Russell of Bedford; John Russell of Bedford; John Russell, 6:e hertig av Bedford; John Russell of Bedford; John Russell of Bedford; John Russell; John Russell of Bedford; John Russell, 6th Duke of Bedford; John Russell, 6. Duke of Bedford; John Russell of Bedford; A. John Russell, 6th Duke of Bedford; John Russell of Bedford; جون راسل، الدوق السادس من بيدفورد; Τζον Ράσελ, 6ος δούκας του Μπέντφορντ; 제6대 베드퍼드 공작 존 러셀; politico britannico; ব্রিটিশ রাজনীতিবিদ; politicien britannique né en 1766; Suurbritannia poliitik; polític britànic; britischer Politiker; British politician; 6. Bedford Dükü; британский аристократ и политик; britisk politiker, 6. hertug av Bedford; سياسي بريطاني; British politician (1766-1839); brittiläinen poliitikko; британський політик; Brits botanicus (1766-1839); politikan britanik; político whig británico; politician britanic; 영국 정치인; político británico; British politician; פוליטיקאי בריטי; botanegydd, gwleidydd, pendefig (1766-1839); J.Russell; John Russell of Bedford; J.Russell; John Russell of Bedford; Bedford, John Russell, 6 hertig av; J.Russell; John Russell of Bedford; John Russell of Bedford; J.Russell; John Russell 6º Duque de Bedford; John Russell, 6 Duque de Bedford; John Russell 6 Duque de Bedford; John Russell, 6º Duque de Bedford; J Russell; John Russell duque de Bedford; John Russell of Bedford; J.Russell; Рассел, Джон, 6-й герцог Бедфорд; J.Russell; John Russell of Bedford; 존 러셀; 존 베드퍼드; John Russell of Bedford; J. Russell; John Bedford; Lord John Russell; John Russell of Bedford; J.Russell; John Russell of Bedford</nowiki>