File:Laying out for boiler makers and sheet metal workers; a practical treatise on the layout of boilers, stacks, tanks, pipes, elbows, and miscellaneous sheet metal work (1907) (14779220772).jpg

Identifier: layingoutforboil01newy (find matches)
Title: Laying out for boiler makers and sheet metal workers; a practical treatise on the layout of boilers, stacks, tanks, pipes, elbows, and miscellaneous sheet metal work
Year: 1907 (1900s)
Authors:
Subjects: Steam-boilers Sheet-metal work
Publisher: New York, The Boiler maker
Contributing Library: The Library of Congress
Digitizing Sponsor: The Library of Congress

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th of net section ofplate. 3 X .69029 X 42000 = 86,976.54 pounds, strength of threerivets in single shear, 100 X 78750 -^ 103,359 = 7(> percentefficiency of joint. See Fig. i.The British Columbia formula gives the following results:P = Pitch of rivets in inches.D ^ Diameter of rivets in inches.A = Area of one rivet in square inches.A^ = Number of rivets in one pitch (greatest pitch).Y = 23 for steel rivets and plate.y = 28 for steel rivets and plate.T = Thickness of plate n inches.C = I for Ian. HOW TO LAY OUT A TUBULAR BOILER 33 C = 1.75 for double butt strap joint.F = Factor of safety.% =: Percentage of plate between greatest pitch of rivets.%* = Percentage of rivet section as compared with solidplate. 100 X (P — D)— = % for iron or steel plates. (Pitch — diameter of rivet hole) X 100 Pitch = % of strength ofplate, at joint,compared withsolid plate. (Area of rivets X number rows of rivets) X 100 Pitch X thickness of plate% of strength of rivets as compared with solid plate.
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Pig. 3 100 X /^ X A^ X F X C X ^ % for steel plates 4 X y X T X P rivets.100 (P— D) = (3.9375 — -9375) 100 =: 3 X 100 = 300.:)00 -^ 3.937s = 76 % net section plate between rivets.100 X .69029 X 3 X 23 X 4-20 ■ = 104% = percentage of strength 4 X 28 X 3-9375 X -4375 . of rivets compared to plate. Note.—F in this example is factor on longitudinal seamonly. The computation, according to the Canadian marine law, isgiven below: Fig. 8 Taking the same example, when we obtain 104 percent withB. C. formula, we find as follows:.69029 X 3 X 100 ^ 120 percent. 3-9375 X -4375 Note.—It will be noticed that the Canadian marine law doesnot take into consideration the factor of safety as is done in theBritish Columbia law. Also in the formula for the percentageof strength of the rivets as compared with the solid plate, noaccount is taken of the fact that the shearing strength of therivets is different from the tensile strength of the plate. As-suming that the shearing strength of the rivets

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