File:Formula1a.gif

${\displaystyle F(x)={\begin{cases}{\frac {A\cdot \vert x\vert }{1+\ln(A)}}&0\leq \vert x\vert <{\frac {1}{A}}\\{\frac {\operatorname {sgn}(x)\cdot (1+\ln(A\vert x\vert ))}{1+\ln(A)}}&{\frac {1}{A}}\leq \vert x\vert \leq 1\end{cases}}}$

In your article, replace the image with:

<math>F(x) = 
\begin{cases}
\frac{A \cdot \vert x \vert}{1 + \ln(A)} & 0 \le \vert x \vert < \frac{1}{A} \\
\frac{\sgn(x) \cdot (1 + \ln(A \vert x \vert))}{1 + \ln(A)} & \frac{1}{A} \le \vert x \vert \le 1
\end{cases}</math>

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