File:FS RC bw.png

Summary[edit]

Black area in the normalised case[edit]

0) Area of the base triangle ${\displaystyle A_{0}=1}$
1) Area of the inscribed circle ${\displaystyle A_{1}=\pi \left({\frac {3-2{\sqrt {2}}}{2}}\right)\cdot \left({\sqrt {2}}\right)^{2}=\pi (3-2{\sqrt {2}})\quad \approx 0.539}$
B) Area of black color ${\displaystyle B=A_{0}-A_{1}=1-\pi (3-2{\sqrt {2}})\quad \approx 0.461}$

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